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Oracle 1z1-819 certification exam is designed for professionals who want to validate their skills and knowledge in Java SE 11 development. 1z1-819 exam tests candidates on their ability to write code using Java SE 11 programming language, design and implement algorithms, and develop robust and scalable applications. Java SE 11 Developer certification is ideal for developers who want to advance their career in Java programming and demonstrate their proficiency to potential employers.

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Oracle 1Z0-819 exam covers a range of topics such as Java basics, Java data types, Java arrays and collections, Java I/O, Java concurrency, Java annotations, and Java modules. It also covers topics such as Java lambda expressions, Java streams, Java functional interfaces, and Java date/time API. 1z1-819 exam is intended to measure the developer's ability to write efficient, maintainable, and scalable Java code.

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Oracle Java SE 11 Developer Sample Questions (Q33-Q38):

NEW QUESTION # 33
Given:

What is the result?

A. nothing
B. 5 4 3 2 1
C. 5 4 3 2 1 4 3 2 1 3 2 1 2 1 1
D. 0

Answer: A

Explanation:

NEW QUESTION # 34
Given:

Which code fragment on line 1 makes the m map contain the employee with the highest salary for each neighborhood?
A)

B)

C)

D)

A. Option D
B. Option A
C. Option C
D. Option B

Answer: A

NEW QUESTION # 35
Given:

What is the result?

A. 0
B. An exception is thrown at runtime.
C. 1
D. 2

Answer: D

Explanation:

NEW QUESTION # 36
Given:

What is the result?

A. java.lang.ArrayIndexOutOfBoundsException thrown
B. [0,0] = Red[0,1] = White[1,0] = Black[1,1] = Blue[2,0] = Yellow[2,1] = Green[3,0] = Violet
C. [0,0] = Red[1,0] = Black[2,0] = Blue
D. [0,0] = Red[0,1] = White[1,0] = Black[2,0] = Blue[2,1] = Yellow[2,2] = Green[2,3] = Violet

Answer: D

Explanation:

NEW QUESTION # 37
Given the code fragment:
public void foo(Function<Integer, String> fun) {...}
Which two compile? (Choose two.)

A. foo( toHexString )
B. foo( n -> n + 1 )
C. foo( Integer::toHexString )
D. foo( n::toHexString )
E. foo( n -> Integer::toHexString )
F. foo( n -> Integer.toHexString(n) )
G. foo( (int n) -> Integer.toHexString(n) )
H. foo( int n -> Integer.toHexString(n) )

Answer: B,F

Explanation:
Explanation/Reference:

NEW QUESTION # 38
......

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